Samsung WB100 vs. Fujifilm FinePix S2980

Comparison

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WB100 image
vs
FinePix S2980 image
Samsung WB100 Fujifilm FinePix S2980
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Megapixels
16.20
14.00
Max. image resolution
4608 x 3456
4288 x 3216

Sensor

Sensor type
CCD
n/a
Sensor size
1/2.3" (~ 6.16 x 4.62 mm)
1/2.3" (~ 6.16 x 4.62 mm)
Sensor resolution
4642 x 3490
4315 x 3244
Diagonal
7.70 mm
7.70 mm
Sensor size comparison
Sensor size is generally a good indicator of the quality of the camera. Sensors can vary greatly in size. As a general rule, the bigger the sensor, the better the image quality.

Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.

Learn more about sensor sizes »

Actual sensor size

Note: Actual size is set to screen → change »
vs
1 : 1
(ratio)
Samsung WB100 Fujifilm FinePix S2980
Surface area:
28.46 mm² vs 28.46 mm²
Difference: 0 mm² (0%)
WB100 and S2980 sensors are the same size.
Pixel pitch
1.33 µm
1.43 µm
Pixel pitch tells you the distance from the center of one pixel (photosite) to the center of the next. It tells you how close the pixels are to each other.

The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.
Difference: 0.1 µm (8%)
Pixel pitch of S2980 is approx. 8% higher than pixel pitch of WB100.
Pixel area
1.77 µm²
2.04 µm²
Pixel or photosite area affects how much light per pixel can be gathered. The larger it is the more light can be collected by a single pixel.

Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.
Relative pixel sizes:
vs
Pixel area difference: 0.27 µm² (15%)
A pixel on Fujifilm S2980 sensor is approx. 15% bigger than a pixel on Samsung WB100.
Pixel density
56.79 MP/cm²
49.07 MP/cm²
Pixel density tells you how many million pixels fit or would fit in one square cm of the sensor.

Higher pixel density means smaller pixels and lower pixel density means larger pixels.
Difference: 7.72 µm (16%)
Samsung WB100 has approx. 16% higher pixel density than Fujifilm S2980.
To learn about the accuracy of these numbers, click here.

Specs

Samsung WB100
Fujifilm S2980
Crop factor
5.62
5.62
Total megapixels
16.40
Effective megapixels
16.20
Optical zoom
26x
Digital zoom
Yes
ISO sensitivity
Auto, 80, 100, 200, 400, 800, 1600, 3200
RAW
Manual focus
Normal focus range
80 cm
Macro focus range
10 cm
Focal length (35mm equiv.)
22.3 - 580 mm
Aperture priority
No
Max. aperture
f3.1 - f5.9
Max. aperture (35mm equiv.)
f17.4 - f33.2
n/a
Metering
Centre weighted, Multi-pattern, Spot
Exposure compensation
±2 EV (in 1/3 EV steps)
Shutter priority
No
Min. shutter speed
8 sec
Max. shutter speed
1/2000 sec
Built-in flash
External flash
Viewfinder
None
Electronic
White balance presets
5
Screen size
3"
Screen resolution
230,000 dots
Video capture
Max. video resolution
Storage types
SD/SDHC/SDXC
USB
USB 2.0 (480 Mbit/sec)
HDMI
Wireless
GPS
Battery
4×AA Type
Weight
408 g
Dimensions
114.48 x 79.26 x 86.45 mm
Year
2012
2011



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Diagonal

Diagonal is calculated by the use of Pythagorean theorem:
Diagonal =  w² + h²
where w = sensor width and h = sensor height

Samsung WB100 diagonal

The diagonal of WB100 sensor is not 1/2.3 or 0.43" (11 mm) as you might expect, but approximately two thirds of that value - 7.7 mm. If you want to know why, see sensor sizes.

w = 6.16 mm
h = 4.62 mm
Diagonal =  6.16² + 4.62²   = 7.70 mm

Fujifilm S2980 diagonal

The diagonal of S2980 sensor is not 1/2.3 or 0.43" (11 mm) as you might expect, but approximately two thirds of that value - 7.7 mm. If you want to know why, see sensor sizes.

w = 6.16 mm
h = 4.62 mm
Diagonal =  6.16² + 4.62²   = 7.70 mm


Surface area

Surface area is calculated by multiplying the width and the height of a sensor.

WB100 sensor area

Width = 6.16 mm
Height = 4.62 mm

Surface area = 6.16 × 4.62 = 28.46 mm²

S2980 sensor area

Width = 6.16 mm
Height = 4.62 mm

Surface area = 6.16 × 4.62 = 28.46 mm²


Pixel pitch

Pixel pitch is the distance from the center of one pixel to the center of the next measured in micrometers (µm). It can be calculated with the following formula:
Pixel pitch =   sensor width in mm  × 1000
sensor resolution width in pixels

WB100 pixel pitch

Sensor width = 6.16 mm
Sensor resolution width = 4642 pixels
Pixel pitch =   6.16  × 1000  = 1.33 µm
4642

S2980 pixel pitch

Sensor width = 6.16 mm
Sensor resolution width = 4315 pixels
Pixel pitch =   6.16  × 1000  = 1.43 µm
4315


Pixel area

The area of one pixel can be calculated by simply squaring the pixel pitch:
Pixel area = pixel pitch²

You could also divide sensor surface area with effective megapixels:
Pixel area =   sensor surface area in mm²
effective megapixels

WB100 pixel area

Pixel pitch = 1.33 µm

Pixel area = 1.33² = 1.77 µm²

S2980 pixel area

Pixel pitch = 1.43 µm

Pixel area = 1.43² = 2.04 µm²


Pixel density

Pixel density can be calculated with the following formula:
Pixel density =  ( sensor resolution width in pixels )² / 1000000
sensor width in cm

One could also use this formula:
Pixel density =   effective megapixels × 1000000  / 10000
sensor surface area in mm²

WB100 pixel density

Sensor resolution width = 4642 pixels
Sensor width = 0.616 cm

Pixel density = (4642 / 0.616)² / 1000000 = 56.79 MP/cm²

S2980 pixel density

Sensor resolution width = 4315 pixels
Sensor width = 0.616 cm

Pixel density = (4315 / 0.616)² / 1000000 = 49.07 MP/cm²


Sensor resolution

Sensor resolution is calculated from sensor size and effective megapixels. It's slightly higher than maximum (not interpolated) image resolution which is usually stated on camera specifications. Sensor resolution is used in pixel pitch, pixel area, and pixel density formula. For sake of simplicity, we're going to calculate it in 3 stages.

1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.

2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:
(X × r) × X = effective megapixels × 1000000    →   
X =  effective megapixels × 1000000
r
3. To get sensor resolution we then multiply X with the corresponding ratio:

Resolution horizontal: X × r
Resolution vertical: X

WB100 sensor resolution

Sensor width = 6.16 mm
Sensor height = 4.62 mm
Effective megapixels = 16.20
r = 6.16/4.62 = 1.33
X =  16.20 × 1000000  = 3490
1.33
Resolution horizontal: X × r = 3490 × 1.33 = 4642
Resolution vertical: X = 3490

Sensor resolution = 4642 x 3490

S2980 sensor resolution

Sensor width = 6.16 mm
Sensor height = 4.62 mm
Effective megapixels = 14.00
r = 6.16/4.62 = 1.33
X =  14.00 × 1000000  = 3244
1.33
Resolution horizontal: X × r = 3244 × 1.33 = 4315
Resolution vertical: X = 3244

Sensor resolution = 4315 x 3244


Crop factor

Crop factor or focal length multiplier is calculated by dividing the diagonal of 35 mm film (43.27 mm) with the diagonal of the sensor.
Crop factor =   43.27 mm
sensor diagonal in mm


WB100 crop factor

Sensor diagonal in mm = 7.70 mm
Crop factor =   43.27  = 5.62
7.70

S2980 crop factor

Sensor diagonal in mm = 7.70 mm
Crop factor =   43.27  = 5.62
7.70

35 mm equivalent aperture

Equivalent aperture (in 135 film terms) is calculated by multiplying lens aperture with crop factor (a.k.a. focal length multiplier).

WB100 equivalent aperture

Crop factor = 5.62
Aperture = f3.1 - f5.9

35-mm equivalent aperture = (f3.1 - f5.9) × 5.62 = f17.4 - f33.2

S2980 equivalent aperture

Aperture is a lens characteristic, so it's calculated only for fixed lens cameras. If you want to know the equivalent aperture for Fujifilm S2980, take the aperture of the lens you're using and multiply it with crop factor.

Crop factor for Fujifilm S2980 is 5.62

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