Nokia Lumia 1020 vs. Fujifilm X20

Comparison

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Lumia 1020 image
vs
X20 image
Nokia Lumia 1020 Fujifilm X20
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Megapixels
41.33
12.00
Max. image resolution
7136 x 5360
4000 x 3000

Sensor

Sensor type
CMOS
CMOS
Sensor size
8.64 x 6 mm
2/3" (~ 8.8 x 6.6 mm)
Sensor resolution
7714 x 5357
3995 x 3004
Diagonal
10.52 mm
11.00 mm
Sensor size comparison
Sensor size is generally a good indicator of the quality of the camera. Sensors can vary greatly in size. As a general rule, the bigger the sensor, the better the image quality.

Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.

Learn more about sensor sizes »

Actual sensor size

Note: Actual size is set to screen → change »
vs
1 : 1.12
(ratio)
Nokia Lumia 1020 Fujifilm X20
Surface area:
51.84 mm² vs 58.08 mm²
Difference: 6.24 mm² (12%)
X20 sensor is approx. 1.12x bigger than Lumia 1020 sensor.
Pixel pitch
1.12 µm
2.2 µm
Pixel pitch tells you the distance from the center of one pixel (photosite) to the center of the next. It tells you how close the pixels are to each other.

The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.
Difference: 1.08 µm (96%)
Pixel pitch of X20 is approx. 96% higher than pixel pitch of Lumia 1020.
Pixel area
1.25 µm²
4.84 µm²
Pixel or photosite area affects how much light per pixel can be gathered. The larger it is the more light can be collected by a single pixel.

Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.
Relative pixel sizes:
vs
Pixel area difference: 3.59 µm² (287%)
A pixel on Fujifilm X20 sensor is approx. 287% bigger than a pixel on Nokia Lumia 1020.
Pixel density
79.71 MP/cm²
20.61 MP/cm²
Pixel density tells you how many million pixels fit or would fit in one square cm of the sensor.

Higher pixel density means smaller pixels and lower pixel density means larger pixels.
Difference: 59.1 µm (287%)
Nokia Lumia 1020 has approx. 287% higher pixel density than Fujifilm X20.
To learn about the accuracy of these numbers, click here.

Specs

Nokia Lumia 1020
Fujifilm X20
Crop factor
4.11
3.93
Total megapixels
41.33
Effective megapixels
12.00
Optical zoom
4x
Digital zoom
Yes
Yes
ISO sensitivity
100, 200, 400, 800, 1600, 3200
Auto, 100, 200, 250, 320, 400, 500, 640, 800, 1000, 1250, 1600, 2000, 2500, 3200, 4000, 5000, 6400, 12800
RAW
Manual focus
Normal focus range
50 cm
Macro focus range
15 cm
1 cm
Focal length (35mm equiv.)
27 mm
28 - 112 mm
Aperture priority
No
Yes
Max. aperture
f2.2
f2.0 - f2.8
Max. aperture (35mm equiv.)
f9
f7.9 - f11
Metering
Multi, Average, Spot
Exposure compensation
±3 EV (in 1/3 EV steps)
±2 EV (in 1/3 EV steps)
Shutter priority
No
Yes
Min. shutter speed
4 sec
30 sec
Max. shutter speed
1/16000 sec
1/4000 sec
Built-in flash
External flash
Viewfinder
Optical (tunnel)
White balance presets
4
7
Screen size
4,5"
2.8"
Screen resolution
1280 x 768 dots
460,000 dots
Video capture
Max. video resolution
1920x1080 (30p)
1920x1080 (60p)
Storage types
32 GB on-board memory
SD/SDHC/SDXC
USB
USB 2.0 (480 Mbit/sec)
USB 2.0 (480 Mbit/sec)
HDMI
Wireless
GPS
Battery
BV-5XW
Lithium-Ion NP-50 rechargeable battery
Weight
158 g
353 g
Dimensions
130.4 x 71.4 x 10.4 mm
117 x 69.6 x 56.8 mm
Year
2013
2013



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Diagonal

Diagonal is calculated by the use of Pythagorean theorem:
Diagonal =  w² + h²
where w = sensor width and h = sensor height

Nokia Lumia 1020 diagonal

w = 8.64 mm
h = 6.00 mm
Diagonal =  8.64² + 6.00²   = 10.52 mm

Fujifilm X20 diagonal

The diagonal of X20 sensor is not 2/3 or 0.67" (16.9 mm) as you might expect, but approximately two thirds of that value - 11 mm. If you want to know why, see sensor sizes.

w = 8.80 mm
h = 6.60 mm
Diagonal =  8.80² + 6.60²   = 11.00 mm


Surface area

Surface area is calculated by multiplying the width and the height of a sensor.

Lumia 1020 sensor area

Width = 8.64 mm
Height = 6.00 mm

Surface area = 8.64 × 6.00 = 51.84 mm²

X20 sensor area

Width = 8.80 mm
Height = 6.60 mm

Surface area = 8.80 × 6.60 = 58.08 mm²


Pixel pitch

Pixel pitch is the distance from the center of one pixel to the center of the next measured in micrometers (µm). It can be calculated with the following formula:
Pixel pitch =   sensor width in mm  × 1000
sensor resolution width in pixels

Lumia 1020 pixel pitch

Sensor width = 8.64 mm
Sensor resolution width = 7714 pixels
Pixel pitch =   8.64  × 1000  = 1.12 µm
7714

X20 pixel pitch

Sensor width = 8.80 mm
Sensor resolution width = 3995 pixels
Pixel pitch =   8.80  × 1000  = 2.2 µm
3995


Pixel area

The area of one pixel can be calculated by simply squaring the pixel pitch:
Pixel area = pixel pitch²

You could also divide sensor surface area with effective megapixels:
Pixel area =   sensor surface area in mm²
effective megapixels

Lumia 1020 pixel area

Pixel pitch = 1.12 µm

Pixel area = 1.12² = 1.25 µm²

X20 pixel area

Pixel pitch = 2.2 µm

Pixel area = 2.2² = 4.84 µm²


Pixel density

Pixel density can be calculated with the following formula:
Pixel density =  ( sensor resolution width in pixels )² / 1000000
sensor width in cm

One could also use this formula:
Pixel density =   effective megapixels × 1000000  / 10000
sensor surface area in mm²

Lumia 1020 pixel density

Sensor resolution width = 7714 pixels
Sensor width = 0.864 cm

Pixel density = (7714 / 0.864)² / 1000000 = 79.71 MP/cm²

X20 pixel density

Sensor resolution width = 3995 pixels
Sensor width = 0.88 cm

Pixel density = (3995 / 0.88)² / 1000000 = 20.61 MP/cm²


Sensor resolution

Sensor resolution is calculated from sensor size and effective megapixels. It's slightly higher than maximum (not interpolated) image resolution which is usually stated on camera specifications. Sensor resolution is used in pixel pitch, pixel area, and pixel density formula. For sake of simplicity, we're going to calculate it in 3 stages.

1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.

2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:
(X × r) × X = effective megapixels × 1000000    →   
X =  effective megapixels × 1000000
r
3. To get sensor resolution we then multiply X with the corresponding ratio:

Resolution horizontal: X × r
Resolution vertical: X

Lumia 1020 sensor resolution

Sensor width = 8.64 mm
Sensor height = 6.00 mm
Effective megapixels = 41.33
r = 8.64/6.00 = 1.44
X =  41.33 × 1000000  = 5357
1.44
Resolution horizontal: X × r = 5357 × 1.44 = 7714
Resolution vertical: X = 5357

Sensor resolution = 7714 x 5357

X20 sensor resolution

Sensor width = 8.80 mm
Sensor height = 6.60 mm
Effective megapixels = 12.00
r = 8.80/6.60 = 1.33
X =  12.00 × 1000000  = 3004
1.33
Resolution horizontal: X × r = 3004 × 1.33 = 3995
Resolution vertical: X = 3004

Sensor resolution = 3995 x 3004


Crop factor

Crop factor or focal length multiplier is calculated by dividing the diagonal of 35 mm film (43.27 mm) with the diagonal of the sensor.
Crop factor =   43.27 mm
sensor diagonal in mm


Lumia 1020 crop factor

Sensor diagonal in mm = 10.52 mm
Crop factor =   43.27  = 4.11
10.52

X20 crop factor

Sensor diagonal in mm = 11.00 mm
Crop factor =   43.27  = 3.93
11.00

35 mm equivalent aperture

Equivalent aperture (in 135 film terms) is calculated by multiplying lens aperture with crop factor (a.k.a. focal length multiplier).

Lumia 1020 equivalent aperture

Crop factor = 4.11
Aperture = f2.2

35-mm equivalent aperture = (f2.2) × 4.11 = f9

X20 equivalent aperture

Crop factor = 3.93
Aperture = f2.0 - f2.8

35-mm equivalent aperture = (f2.0 - f2.8) × 3.93 = f7.9 - f11

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