GE J1458W vs. Samsung ES10

Comparison

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J1458W image
vs
ES10 image
GE J1458W Samsung ES10
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Megapixels
14.10
8.30
Max. image resolution
4320 x 3240
3264 x 2448

Sensor

Sensor type
n/a
n/a
Sensor size
1/2.3" (~ 6.16 x 4.62 mm)
1/2.5" (~ 5.75 x 4.32 mm)
Sensor resolution
4330 x 3256
3322 x 2498
Diagonal
7.70 mm
7.19 mm
Sensor size comparison
Sensor size is generally a good indicator of the quality of the camera. Sensors can vary greatly in size. As a general rule, the bigger the sensor, the better the image quality.

Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.

Learn more about sensor sizes »

Actual sensor size

Note: Actual size is set to screen → change »
vs
1.15 : 1
(ratio)
GE J1458W Samsung ES10
Surface area:
28.46 mm² vs 24.84 mm²
Difference: 3.62 mm² (15%)
J1458W sensor is approx. 1.15x bigger than ES10 sensor.
Note: You are comparing cameras of different generations. There is a 3 year gap between GE J1458W (2012) and Samsung ES10 (2009). All things being equal, newer sensor generations generally outperform the older.
Pixel pitch
1.42 µm
1.73 µm
Pixel pitch tells you the distance from the center of one pixel (photosite) to the center of the next. It tells you how close the pixels are to each other.

The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.
Difference: 0.31 µm (22%)
Pixel pitch of ES10 is approx. 22% higher than pixel pitch of J1458W.
Pixel area
2.02 µm²
2.99 µm²
Pixel or photosite area affects how much light per pixel can be gathered. The larger it is the more light can be collected by a single pixel.

Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.
Relative pixel sizes:
vs
Pixel area difference: 0.97 µm² (48%)
A pixel on Samsung ES10 sensor is approx. 48% bigger than a pixel on GE J1458W.
Pixel density
49.41 MP/cm²
33.38 MP/cm²
Pixel density tells you how many million pixels fit or would fit in one square cm of the sensor.

Higher pixel density means smaller pixels and lower pixel density means larger pixels.
Difference: 16.03 µm (48%)
GE J1458W has approx. 48% higher pixel density than Samsung ES10.
To learn about the accuracy of these numbers, click here.



Specs

GE J1458W
Samsung ES10
Crop factor
5.62
6.02
Total megapixels
Effective megapixels
Optical zoom
Yes
Digital zoom
Yes
ISO sensitivity
Auto, 80, 100, 200, 400, 800, 1600
RAW
Manual focus
Normal focus range
80 cm
Macro focus range
10 cm
Focal length (35mm equiv.)
38 - 114 mm
Aperture priority
No
Max. aperture
f2.8 - f5.2
Max. aperture (35mm equiv.)
n/a
f16.9 - f31.3
Metering
Centre weighted, Multi Spot
Exposure compensation
±2 EV (in 1/3 EV steps)
Shutter priority
Yes
Min. shutter speed
8 sec
Max. shutter speed
1/2000 sec
Built-in flash
External flash
Viewfinder
Optical
None
White balance presets
6
Screen size
2.5"
Screen resolution
230,000 dots
Video capture
Max. video resolution
Storage types
SDHC, Secure Digital
USB
USB 2.0 (480 Mbit/sec)
HDMI
Wireless
GPS
Battery
2x AA
Weight
120 g
Dimensions
94.1 x 62.7 x 25.2 mm
Year
2012
2009




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Diagonal

Diagonal is calculated by the use of Pythagorean theorem:
Diagonal =  w² + h²
where w = sensor width and h = sensor height

GE J1458W diagonal

The diagonal of J1458W sensor is not 1/2.3 or 0.43" (11 mm) as you might expect, but approximately two thirds of that value - 7.7 mm. If you want to know why, see sensor sizes.

w = 6.16 mm
h = 4.62 mm
Diagonal =  6.16² + 4.62²   = 7.70 mm

Samsung ES10 diagonal

The diagonal of ES10 sensor is not 1/2.5 or 0.4" (10.2 mm) as you might expect, but approximately two thirds of that value - 7.19 mm. If you want to know why, see sensor sizes.

w = 5.75 mm
h = 4.32 mm
Diagonal =  5.75² + 4.32²   = 7.19 mm


Surface area

Surface area is calculated by multiplying the width and the height of a sensor.

J1458W sensor area

Width = 6.16 mm
Height = 4.62 mm

Surface area = 6.16 × 4.62 = 28.46 mm²

ES10 sensor area

Width = 5.75 mm
Height = 4.32 mm

Surface area = 5.75 × 4.32 = 24.84 mm²


Pixel pitch

Pixel pitch is the distance from the center of one pixel to the center of the next measured in micrometers (µm). It can be calculated with the following formula:
Pixel pitch =   sensor width in mm  × 1000
sensor resolution width in pixels

J1458W pixel pitch

Sensor width = 6.16 mm
Sensor resolution width = 4330 pixels
Pixel pitch =   6.16  × 1000  = 1.42 µm
4330

ES10 pixel pitch

Sensor width = 5.75 mm
Sensor resolution width = 3322 pixels
Pixel pitch =   5.75  × 1000  = 1.73 µm
3322


Pixel area

The area of one pixel can be calculated by simply squaring the pixel pitch:
Pixel area = pixel pitch²

You could also divide sensor surface area with effective megapixels:
Pixel area =   sensor surface area in mm²
effective megapixels

J1458W pixel area

Pixel pitch = 1.42 µm

Pixel area = 1.42² = 2.02 µm²

ES10 pixel area

Pixel pitch = 1.73 µm

Pixel area = 1.73² = 2.99 µm²


Pixel density

Pixel density can be calculated with the following formula:
Pixel density =  ( sensor resolution width in pixels )² / 1000000
sensor width in cm

One could also use this formula:
Pixel density =   effective megapixels × 1000000  / 10000
sensor surface area in mm²

J1458W pixel density

Sensor resolution width = 4330 pixels
Sensor width = 0.616 cm

Pixel density = (4330 / 0.616)² / 1000000 = 49.41 MP/cm²

ES10 pixel density

Sensor resolution width = 3322 pixels
Sensor width = 0.575 cm

Pixel density = (3322 / 0.575)² / 1000000 = 33.38 MP/cm²


Sensor resolution

Sensor resolution is calculated from sensor size and effective megapixels. It's slightly higher than maximum (not interpolated) image resolution which is usually stated on camera specifications. Sensor resolution is used in pixel pitch, pixel area, and pixel density formula. For sake of simplicity, we're going to calculate it in 3 stages.

1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.

2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:
(X × r) × X = effective megapixels × 1000000    →   
X =  effective megapixels × 1000000
r
3. To get sensor resolution we then multiply X with the corresponding ratio:

Resolution horizontal: X × r
Resolution vertical: X

J1458W sensor resolution

Sensor width = 6.16 mm
Sensor height = 4.62 mm
Effective megapixels = 14.10
r = 6.16/4.62 = 1.33
X =  14.10 × 1000000  = 3256
1.33
Resolution horizontal: X × r = 3256 × 1.33 = 4330
Resolution vertical: X = 3256

Sensor resolution = 4330 x 3256

ES10 sensor resolution

Sensor width = 5.75 mm
Sensor height = 4.32 mm
Effective megapixels = 8.30
r = 5.75/4.32 = 1.33
X =  8.30 × 1000000  = 2498
1.33
Resolution horizontal: X × r = 2498 × 1.33 = 3322
Resolution vertical: X = 2498

Sensor resolution = 3322 x 2498


Crop factor

Crop factor or focal length multiplier is calculated by dividing the diagonal of 35 mm film (43.27 mm) with the diagonal of the sensor.
Crop factor =   43.27 mm
sensor diagonal in mm


J1458W crop factor

Sensor diagonal in mm = 7.70 mm
Crop factor =   43.27  = 5.62
7.70

ES10 crop factor

Sensor diagonal in mm = 7.19 mm
Crop factor =   43.27  = 6.02
7.19

35 mm equivalent aperture

Equivalent aperture (in 135 film terms) is calculated by multiplying lens aperture with crop factor (a.k.a. focal length multiplier).

J1458W equivalent aperture

Aperture is a lens characteristic, so it's calculated only for fixed lens cameras. If you want to know the equivalent aperture for GE J1458W, take the aperture of the lens you're using and multiply it with crop factor.

Crop factor for GE J1458W is 5.62

ES10 equivalent aperture

Crop factor = 6.02
Aperture = f2.8 - f5.2

35-mm equivalent aperture = (f2.8 - f5.2) × 6.02 = f16.9 - f31.3

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