HP Photosmart 935 vs. Nokia Lumia 1020
Comparison
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| HP Photosmart 935 | Nokia Lumia 1020 | ||||
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Megapixels
5.24
41.33
Max. image resolution
2608 x 1952
7136 x 5360
Sensor
Sensor type
CCD
CMOS
Sensor size
1/1.8" (~ 7.11 x 5.33 mm)
8.64 x 6 mm
Sensor size comparison
Sensor size is generally a good indicator of the quality of the camera.
Sensors can vary greatly in size. As a general rule, the bigger the
sensor, the better the image quality.
Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.
Learn more about sensor sizes »
Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.
Learn more about sensor sizes »
Actual sensor size
Note: Actual size is set to screen → change »
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| 1 | : | 1.37 |
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| HP Photosmart 935 | Nokia Lumia 1020 | |
Surface area:
| 37.90 mm² | vs | 51.84 mm² |
Difference: 13.94 mm² (37%)
Lumia 1020 sensor is approx. 1.37x bigger than 935 sensor.
Note: You are comparing sensors of very different generations.
There is a gap of 10 years between HP 935 (2003) and Nokia Lumia 1020 (2013).
Ten years is a lot of time in terms
of technology, meaning newer sensors are overall much more
efficient than the older ones.
Pixel pitch tells you the distance from the center of one pixel (photosite) to the center of the next. It tells you how close the pixels are to each other.
The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.
The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.
Pixel or photosite area affects how much light per pixel can be gathered.
The larger it is the more light can be collected by a single pixel.
Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.
Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.
Relative pixel sizes:
vs
Pixel area difference: 5.99 µm² (479%)
A pixel on HP 935 sensor is approx. 479% bigger than a pixel on Nokia Lumia 1020.
Pixel density tells you how many million pixels fit or would fit in one
square cm of the sensor.
Higher pixel density means smaller pixels and lower pixel density means larger pixels.
Higher pixel density means smaller pixels and lower pixel density means larger pixels.
To learn about the accuracy of these numbers,
click here.
Specs
HP 935
Nokia Lumia 1020
Total megapixels
41.33
Effective megapixels
Optical zoom
3x
Digital zoom
Yes
Yes
ISO sensitivity
Auto, 50, 100, 200, 400
100, 200, 400, 800, 1600, 3200
RAW
Manual focus
Normal focus range
50 cm
Macro focus range
14 cm
15 cm
Focal length (35mm equiv.)
37 - 111 mm
27 mm
Aperture priority
Yes
No
Max. aperture
f2.6 - f4.8
f2.2
Metering
Centre weighted, Matrix, Spot
Exposure compensation
±2 EV (in 1/2 EV steps)
±3 EV (in 1/3 EV steps)
Shutter priority
No
No
Min. shutter speed
15 sec
4 sec
Max. shutter speed
1/2000 sec
1/16000 sec
Built-in flash
External flash
Viewfinder
Optical (tunnel)
White balance presets
6
4
Screen size
1.5"
4,5"
Screen resolution
113,578 dots
1280 x 768 dots
Video capture
Max. video resolution
1920x1080 (30p)
Storage types
MultiMedia, Secure Digital
32 GB on-board memory
USB
USB 1.0
USB 2.0 (480 Mbit/sec)
HDMI
Wireless
GPS
Battery
AA (2) batteries (NiMH recommended)
BV-5XW
Weight
260 g
158 g
Dimensions
97 x 45 x 67 mm
130.4 x 71.4 x 10.4 mm
Year
2003
2013
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Diagonal
Diagonal is calculated by the use of Pythagorean theorem:
where w = sensor width and h = sensor height
| Diagonal = √ | w² + h² |
HP 935 diagonal
The diagonal of 935 sensor is not 1/1.8 or 0.56" (14.1 mm) as you might expect, but approximately two thirds of
that value - 8.89 mm. If you want to know why, see
sensor sizes.
w = 7.11 mm
h = 5.33 mm
w = 7.11 mm
h = 5.33 mm
| Diagonal = √ | 7.11² + 5.33² | = 8.89 mm |
Nokia Lumia 1020 diagonal
w = 8.64 mm
h = 6.00 mm
h = 6.00 mm
| Diagonal = √ | 8.64² + 6.00² | = 10.52 mm |
Surface area
Surface area is calculated by multiplying the width and the height of a sensor.
935 sensor area
Width = 7.11 mm
Height = 5.33 mm
Surface area = 7.11 × 5.33 = 37.90 mm²
Height = 5.33 mm
Surface area = 7.11 × 5.33 = 37.90 mm²
Lumia 1020 sensor area
Width = 8.64 mm
Height = 6.00 mm
Surface area = 8.64 × 6.00 = 51.84 mm²
Height = 6.00 mm
Surface area = 8.64 × 6.00 = 51.84 mm²
Pixel pitch
Pixel pitch is the distance from the center of one pixel to the center of the
next measured in micrometers (µm). It can be calculated with the following formula:
| Pixel pitch = | sensor width in mm | × 1000 |
| sensor resolution width in pixels |
935 pixel pitch
Sensor width = 7.11 mm
Sensor resolution width = 2640 pixels
Sensor resolution width = 2640 pixels
| Pixel pitch = | 7.11 | × 1000 | = 2.69 µm |
| 2640 |
Lumia 1020 pixel pitch
Sensor width = 8.64 mm
Sensor resolution width = 7714 pixels
Sensor resolution width = 7714 pixels
| Pixel pitch = | 8.64 | × 1000 | = 1.12 µm |
| 7714 |
Pixel area
The area of one pixel can be calculated by simply squaring the pixel pitch:
You could also divide sensor surface area with effective megapixels:
Pixel area = pixel pitch²
You could also divide sensor surface area with effective megapixels:
| Pixel area = | sensor surface area in mm² |
| effective megapixels |
935 pixel area
Pixel pitch = 2.69 µm
Pixel area = 2.69² = 7.24 µm²
Pixel area = 2.69² = 7.24 µm²
Lumia 1020 pixel area
Pixel pitch = 1.12 µm
Pixel area = 1.12² = 1.25 µm²
Pixel area = 1.12² = 1.25 µm²
Pixel density
Pixel density can be calculated with the following formula:
One could also use this formula:
| Pixel density = ( | sensor resolution width in pixels | )² / 1000000 |
| sensor width in cm |
One could also use this formula:
| Pixel density = | effective megapixels × 1000000 | / 10000 |
| sensor surface area in mm² |
935 pixel density
Sensor resolution width = 2640 pixels
Sensor width = 0.711 cm
Pixel density = (2640 / 0.711)² / 1000000 = 13.79 MP/cm²
Sensor width = 0.711 cm
Pixel density = (2640 / 0.711)² / 1000000 = 13.79 MP/cm²
Lumia 1020 pixel density
Sensor resolution width = 7714 pixels
Sensor width = 0.864 cm
Pixel density = (7714 / 0.864)² / 1000000 = 79.71 MP/cm²
Sensor width = 0.864 cm
Pixel density = (7714 / 0.864)² / 1000000 = 79.71 MP/cm²
Sensor resolution
Sensor resolution is calculated from sensor size and effective megapixels. It's slightly higher
than maximum (not interpolated) image resolution which is usually stated on camera specifications.
Sensor resolution is used in pixel pitch, pixel area, and pixel density formula.
For sake of simplicity, we're going to calculate it in 3 stages.
1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.
2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:
3. To get sensor resolution we then multiply X with the corresponding ratio:
Resolution horizontal: X × r
Resolution vertical: X
1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.
2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:
| (X × r) × X = effective megapixels × 1000000 → |
|
Resolution horizontal: X × r
Resolution vertical: X
935 sensor resolution
Sensor width = 7.11 mm
Sensor height = 5.33 mm
Effective megapixels = 5.24
Resolution horizontal: X × r = 1985 × 1.33 = 2640
Resolution vertical: X = 1985
Sensor resolution = 2640 x 1985
Sensor height = 5.33 mm
Effective megapixels = 5.24
| r = 7.11/5.33 = 1.33 |
|
Resolution vertical: X = 1985
Sensor resolution = 2640 x 1985
Lumia 1020 sensor resolution
Sensor width = 8.64 mm
Sensor height = 6.00 mm
Effective megapixels = 41.33
Resolution horizontal: X × r = 5357 × 1.44 = 7714
Resolution vertical: X = 5357
Sensor resolution = 7714 x 5357
Sensor height = 6.00 mm
Effective megapixels = 41.33
| r = 8.64/6.00 = 1.44 |
|
Resolution vertical: X = 5357
Sensor resolution = 7714 x 5357
Crop factor
Crop factor or focal length multiplier is calculated by dividing the diagonal
of 35 mm film (43.27 mm) with the diagonal of the sensor.
| Crop factor = | 43.27 mm |
| sensor diagonal in mm |
935 crop factor
Sensor diagonal in mm = 8.89 mm
| Crop factor = | 43.27 | = 4.87 |
| 8.89 |
Lumia 1020 crop factor
Sensor diagonal in mm = 10.52 mm
| Crop factor = | 43.27 | = 4.11 |
| 10.52 |
35 mm equivalent aperture
Equivalent aperture (in 135 film terms) is calculated by multiplying lens aperture
with crop factor (a.k.a. focal length multiplier).
935 equivalent aperture
Crop factor = 4.87
Aperture = f2.6 - f4.8
35-mm equivalent aperture = (f2.6 - f4.8) × 4.87 = f12.7 - f23.4
Aperture = f2.6 - f4.8
35-mm equivalent aperture = (f2.6 - f4.8) × 4.87 = f12.7 - f23.4
Lumia 1020 equivalent aperture
Crop factor = 4.11
Aperture = f2.2
35-mm equivalent aperture = (f2.2) × 4.11 = f9
Aperture = f2.2
35-mm equivalent aperture = (f2.2) × 4.11 = f9
Enter your screen size (diagonal)
My screen size is
inches
Actual size is currently adjusted to screen.
If your screen (phone, tablet, or monitor) is not in diagonal, then the actual size of a sensor won't be shown correctly.
If your screen (phone, tablet, or monitor) is not in diagonal, then the actual size of a sensor won't be shown correctly.