Nikon Coolpix 100 vs. Fujifilm FinePix S2980
Comparison
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| Nikon Coolpix 100 | Fujifilm FinePix S2980 | ||||
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Megapixels
0.30
14.00
Max. image resolution
512 x 480
4288 x 3216
Sensor
Sensor type
CCD
n/a
Sensor size
1/3" (~ 4.8 x 3.6 mm)
1/2.3" (~ 6.16 x 4.62 mm)
Sensor size comparison
Sensor size is generally a good indicator of the quality of the camera.
Sensors can vary greatly in size. As a general rule, the bigger the
sensor, the better the image quality.
Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.
Learn more about sensor sizes »
Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.
Learn more about sensor sizes »
Actual sensor size
Note: Actual size is set to screen → change »
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| Nikon Coolpix 100 | Fujifilm FinePix S2980 | |
Surface area:
| 17.28 mm² | vs | 28.46 mm² |
Difference: 11.18 mm² (65%)
S2980 sensor is approx. 1.65x bigger than 100 sensor.
Note: You are comparing sensors of vastly different generations.
There is a gap of 14 years between Nikon 100 (1997) and
Fujifilm S2980 (2011).
Fourteen years is a huge amount of time,
technology wise, resulting in newer sensor being much more
efficient than the older one.
Pixel pitch tells you the distance from the center of one pixel (photosite) to the center of the next. It tells you how close the pixels are to each other.
The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.
The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.
Pixel or photosite area affects how much light per pixel can be gathered.
The larger it is the more light can be collected by a single pixel.
Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.
Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.
Relative pixel sizes:
vs
Pixel area difference: 55.57 µm² (2724%)
A pixel on Nikon 100 sensor is approx. 2724% bigger than a pixel on Fujifilm S2980.
Pixel density tells you how many million pixels fit or would fit in one
square cm of the sensor.
Higher pixel density means smaller pixels and lower pixel density means larger pixels.
Higher pixel density means smaller pixels and lower pixel density means larger pixels.
To learn about the accuracy of these numbers,
click here.
Specs
Nikon 100
Fujifilm S2980
Total megapixels
0.30
Effective megapixels
0.30
Optical zoom
1x
Digital zoom
No
ISO sensitivity
100
RAW
Manual focus
Normal focus range
23 cm
Macro focus range
14 cm
Focal length (35mm equiv.)
52 mm
Aperture priority
No
Max. aperture
f2.4 - f3.6
Metering
Multi, Center-weighted, Spot
Exposure compensation
±2 EV (in 1/2 EV steps)
Shutter priority
No
Min. shutter speed
1/45 sec
Max. shutter speed
1/10000 sec
Built-in flash
External flash
Viewfinder
Optical (tunnel)
Electronic
White balance presets
5
Screen size
2"
Screen resolution
130,000 dots
Video capture
Max. video resolution
Storage types
Internal
USB
USB 1.0
HDMI
Wireless
GPS
Battery
AA (4) batteries (NiMH recommended)
Weight
200 g
Dimensions
60 x 155 x 35 mm
Year
1997
2011
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Diagonal
Diagonal is calculated by the use of Pythagorean theorem:
where w = sensor width and h = sensor height
| Diagonal = √ | w² + h² |
Nikon 100 diagonal
The diagonal of 100 sensor is not 1/3 or 0.33" (8.5 mm) as you might expect, but approximately two thirds of
that value - 6 mm. If you want to know why, see
sensor sizes.
w = 4.80 mm
h = 3.60 mm
w = 4.80 mm
h = 3.60 mm
| Diagonal = √ | 4.80² + 3.60² | = 6.00 mm |
Fujifilm S2980 diagonal
The diagonal of S2980 sensor is not 1/2.3 or 0.43" (11 mm) as you might expect, but approximately two thirds of
that value - 7.7 mm. If you want to know why, see
sensor sizes.
w = 6.16 mm
h = 4.62 mm
w = 6.16 mm
h = 4.62 mm
| Diagonal = √ | 6.16² + 4.62² | = 7.70 mm |
Surface area
Surface area is calculated by multiplying the width and the height of a sensor.
100 sensor area
Width = 4.80 mm
Height = 3.60 mm
Surface area = 4.80 × 3.60 = 17.28 mm²
Height = 3.60 mm
Surface area = 4.80 × 3.60 = 17.28 mm²
S2980 sensor area
Width = 6.16 mm
Height = 4.62 mm
Surface area = 6.16 × 4.62 = 28.46 mm²
Height = 4.62 mm
Surface area = 6.16 × 4.62 = 28.46 mm²
Pixel pitch
Pixel pitch is the distance from the center of one pixel to the center of the
next measured in micrometers (µm). It can be calculated with the following formula:
| Pixel pitch = | sensor width in mm | × 1000 |
| sensor resolution width in pixels |
100 pixel pitch
Sensor width = 4.80 mm
Sensor resolution width = 632 pixels
Sensor resolution width = 632 pixels
| Pixel pitch = | 4.80 | × 1000 | = 7.59 µm |
| 632 |
S2980 pixel pitch
Sensor width = 6.16 mm
Sensor resolution width = 4315 pixels
Sensor resolution width = 4315 pixels
| Pixel pitch = | 6.16 | × 1000 | = 1.43 µm |
| 4315 |
Pixel area
The area of one pixel can be calculated by simply squaring the pixel pitch:
You could also divide sensor surface area with effective megapixels:
Pixel area = pixel pitch²
You could also divide sensor surface area with effective megapixels:
| Pixel area = | sensor surface area in mm² |
| effective megapixels |
100 pixel area
Pixel pitch = 7.59 µm
Pixel area = 7.59² = 57.61 µm²
Pixel area = 7.59² = 57.61 µm²
S2980 pixel area
Pixel pitch = 1.43 µm
Pixel area = 1.43² = 2.04 µm²
Pixel area = 1.43² = 2.04 µm²
Pixel density
Pixel density can be calculated with the following formula:
One could also use this formula:
| Pixel density = ( | sensor resolution width in pixels | )² / 1000000 |
| sensor width in cm |
One could also use this formula:
| Pixel density = | effective megapixels × 1000000 | / 10000 |
| sensor surface area in mm² |
100 pixel density
Sensor resolution width = 632 pixels
Sensor width = 0.48 cm
Pixel density = (632 / 0.48)² / 1000000 = 1.73 MP/cm²
Sensor width = 0.48 cm
Pixel density = (632 / 0.48)² / 1000000 = 1.73 MP/cm²
S2980 pixel density
Sensor resolution width = 4315 pixels
Sensor width = 0.616 cm
Pixel density = (4315 / 0.616)² / 1000000 = 49.07 MP/cm²
Sensor width = 0.616 cm
Pixel density = (4315 / 0.616)² / 1000000 = 49.07 MP/cm²
Sensor resolution
Sensor resolution is calculated from sensor size and effective megapixels. It's slightly higher
than maximum (not interpolated) image resolution which is usually stated on camera specifications.
Sensor resolution is used in pixel pitch, pixel area, and pixel density formula.
For sake of simplicity, we're going to calculate it in 3 stages.
1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.
2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:
3. To get sensor resolution we then multiply X with the corresponding ratio:
Resolution horizontal: X × r
Resolution vertical: X
1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.
2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:
| (X × r) × X = effective megapixels × 1000000 → |
|
Resolution horizontal: X × r
Resolution vertical: X
100 sensor resolution
Sensor width = 4.80 mm
Sensor height = 3.60 mm
Effective megapixels = 0.30
Resolution horizontal: X × r = 475 × 1.33 = 632
Resolution vertical: X = 475
Sensor resolution = 632 x 475
Sensor height = 3.60 mm
Effective megapixels = 0.30
| r = 4.80/3.60 = 1.33 |
|
Resolution vertical: X = 475
Sensor resolution = 632 x 475
S2980 sensor resolution
Sensor width = 6.16 mm
Sensor height = 4.62 mm
Effective megapixels = 14.00
Resolution horizontal: X × r = 3244 × 1.33 = 4315
Resolution vertical: X = 3244
Sensor resolution = 4315 x 3244
Sensor height = 4.62 mm
Effective megapixels = 14.00
| r = 6.16/4.62 = 1.33 |
|
Resolution vertical: X = 3244
Sensor resolution = 4315 x 3244
Crop factor
Crop factor or focal length multiplier is calculated by dividing the diagonal
of 35 mm film (43.27 mm) with the diagonal of the sensor.
| Crop factor = | 43.27 mm |
| sensor diagonal in mm |
100 crop factor
Sensor diagonal in mm = 6.00 mm
| Crop factor = | 43.27 | = 7.21 |
| 6.00 |
S2980 crop factor
Sensor diagonal in mm = 7.70 mm
| Crop factor = | 43.27 | = 5.62 |
| 7.70 |
35 mm equivalent aperture
Equivalent aperture (in 135 film terms) is calculated by multiplying lens aperture
with crop factor (a.k.a. focal length multiplier).
100 equivalent aperture
Crop factor = 7.21
Aperture = f2.4 - f3.6
35-mm equivalent aperture = (f2.4 - f3.6) × 7.21 = f17.3 - f26
Aperture = f2.4 - f3.6
35-mm equivalent aperture = (f2.4 - f3.6) × 7.21 = f17.3 - f26
S2980 equivalent aperture
Aperture is a lens characteristic, so it's calculated only for
fixed lens cameras. If you want to know the equivalent aperture for
Fujifilm S2980, take the aperture of the lens
you're using and multiply it with crop factor.
Crop factor for Fujifilm S2980 is 5.62
Crop factor for Fujifilm S2980 is 5.62
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If your screen (phone, tablet, or monitor) is not in diagonal, then the actual size of a sensor won't be shown correctly.