Samsung WB850F vs. Canon PowerShot S110

Comparison

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Samsung WB850F

Canon PowerShot S110

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Megapixels

16.20

12.10

Max. image resolution

4608 x 3456

4000 x 3000

Sensor

Sensor type

CMOS

Sensor size

1/2.3" (~ 6.16 x 4.62 mm)

1/1.7" (~ 7.53 x 5.64 mm)

Sensor resolution

4642 x 3490

4027 x 3005

Diagonal

7.70 mm

9.41 mm

Sensor size comparison

Sensor size is generally a good indicator of the quality of the camera. Sensors can vary greatly in size. As a general rule, the bigger the sensor, the better the image quality.

Bigger sensors are more effective because they have more surface area to capture light. An important factor when comparing digital cameras is also camera generation. Generally, newer sensors will outperform the older.

Learn more about sensor sizes »

Actual sensor size

Note: Actual size is set to screen → change »

	vs
1	:	1.49
(ratio)

Samsung WB850F		Canon PowerShot S110

Surface area:

28.46 mm²

42.47 mm²

Difference: 14.01 mm² (49%)

S110 sensor is approx. 1.49x bigger than WB850F sensor.

Pixel pitch

1.33 µm

1.87 µm

Pixel pitch tells you the distance from the center of one pixel (photosite) to the center of the next. It tells you how close the pixels are to each other.

The bigger the pixel pitch, the further apart they are and the bigger each pixel is. Bigger pixels tend to have better signal to noise ratio and greater dynamic range.

Difference: 0.54 µm (41%)

Pixel pitch of S110 is approx. 41% higher than pixel pitch of WB850F.

Pixel area

1.77 µm²

3.5 µm²

Pixel or photosite area affects how much light per pixel can be gathered. The larger it is the more light can be collected by a single pixel.

Larger pixels have the potential to collect more photons, resulting in greater dynamic range, while smaller pixels provide higher resolutions (more detail) for a given sensor size.

Relative pixel sizes:

Pixel area difference: 1.73 µm² (98%)

A pixel on Canon S110 sensor is approx. 98% bigger than a pixel on Samsung WB850F.

Pixel density

56.79 MP/cm²

28.6 MP/cm²

Pixel density tells you how many million pixels fit or would fit in one square cm of the sensor.

Higher pixel density means smaller pixels and lower pixel density means larger pixels.

Difference: 28.19 µm (99%)

Samsung WB850F has approx. 99% higher pixel density than Canon S110.

To learn about the accuracy of these numbers, click here.

Specs

Samsung WB850F

Canon S110

Crop factor

5.62

4.6

Total megapixels

16.80

13.30

Effective megapixels

16.20

12.10

Optical zoom

21x

Digital zoom

Yes

ISO sensitivity

Auto, 100, 200, 400, 800, 1600, 3200

Auto, 80 - 12800

RAW

Manual focus

Normal focus range

80 cm

30 cm

Macro focus range

5 cm

3 cm

Focal length (35mm equiv.)

23 - 483 mm

24 - 120 mm

Aperture priority

Yes

Max. aperture

f2.8 - f5.9

f2.0 - f5.9

Max. aperture (35mm equiv.)

f15.7 - f33.2

f9.2 - f27.1

Metering

Multi, Center-weighted, Spot

Exposure compensation

±2 EV (in 1/3 EV steps)

±3 EV (in 1/3 EV steps)

Shutter priority

Yes

Min. shutter speed

8 sec

15 sec

Max. shutter speed

1/2000 sec

Built-in flash

External flash

Viewfinder

None

White balance presets

Screen size

Screen resolution

614,000 dots

461,000 dots

Video capture

Max. video resolution

1920x1080 (24p)

Storage types

SD/SDHC/SDXC

USB

USB 2.0 (480 Mbit/sec)

HDMI

Wireless

GPS

Battery

Lithium-Ion SLB-10A rechargeable battery

Lithium-Ion NB-5L rechargeable battery

Weight

341 g

198 g

Dimensions

122 x 90 x 40 mm

98.8 x 59 x 26.9 mm

Year

2012

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Diagonal

Diagonal is calculated by the use of Pythagorean theorem:

Diagonal = √

w² + h²

where w = sensor width and h = sensor height

Samsung WB850F diagonal

The diagonal of WB850F sensor is not 1/2.3 or 0.43" (11 mm) as you might expect, but approximately two thirds of that value - 7.7 mm. If you want to know why, see sensor sizes.

w = 6.16 mm
h = 4.62 mm

Diagonal = √

6.16² + 4.62²

= 7.70 mm

Canon S110 diagonal

The diagonal of S110 sensor is not 1/1.7 or 0.59" (14.9 mm) as you might expect, but approximately two thirds of that value - 9.41 mm. If you want to know why, see sensor sizes.

w = 7.53 mm
h = 5.64 mm

Diagonal = √

7.53² + 5.64²

= 9.41 mm

Surface area

Surface area is calculated by multiplying the width and the height of a sensor.

WB850F sensor area

Width = 6.16 mm
Height = 4.62 mm

Surface area = 6.16 × 4.62 = 28.46 mm²

S110 sensor area

Width = 7.53 mm
Height = 5.64 mm

Surface area = 7.53 × 5.64 = 42.47 mm²

Pixel pitch

Pixel pitch is the distance from the center of one pixel to the center of the next measured in micrometers (µm). It can be calculated with the following formula:

Pixel pitch =	sensor width in mm	× 1000
	sensor resolution width in pixels

WB850F pixel pitch

Sensor width = 6.16 mm
Sensor resolution width = 4642 pixels

Pixel pitch =	6.16	× 1000	= 1.33 µm
	4642

S110 pixel pitch

Sensor width = 7.53 mm
Sensor resolution width = 4027 pixels

Pixel pitch =	7.53	× 1000	= 1.87 µm
	4027

Pixel area

The area of one pixel can be calculated by simply squaring the pixel pitch:

Pixel area = pixel pitch²

You could also divide sensor surface area with effective megapixels:

Pixel area =	sensor surface area in mm²
	effective megapixels

WB850F pixel area

Pixel pitch = 1.33 µm

Pixel area = 1.33² = 1.77 µm²

S110 pixel area

Pixel pitch = 1.87 µm

Pixel area = 1.87² = 3.5 µm²

Pixel density

Pixel density can be calculated with the following formula:

Pixel density = (	sensor resolution width in pixels	)² / 1000000
	sensor width in cm

One could also use this formula:

Pixel density =	effective megapixels × 1000000	/ 10000
	sensor surface area in mm²

WB850F pixel density

Sensor resolution width = 4642 pixels
Sensor width = 0.616 cm

Pixel density = (4642 / 0.616)² / 1000000 = 56.79 MP/cm²

S110 pixel density

Sensor resolution width = 4027 pixels
Sensor width = 0.753 cm

Pixel density = (4027 / 0.753)² / 1000000 = 28.6 MP/cm²

Sensor resolution

Sensor resolution is calculated from sensor size and effective megapixels. It's slightly higher than maximum (not interpolated) image resolution which is usually stated on camera specifications. Sensor resolution is used in pixel pitch, pixel area, and pixel density formula. For sake of simplicity, we're going to calculate it in 3 stages.

1. First we need to find the ratio between horizontal and vertical length by dividing the former with the latter (aspect ratio). It's usually 1.33 (4:3) or 1.5 (3:2), but not always.

2. With the ratio (r) known we can calculate the X from the formula below, where X is a vertical number of pixels:

(X × r) × X = effective megapixels × 1000000 →

X = √	effective megapixels × 1000000
	r

3. To get sensor resolution we then multiply X with the corresponding ratio:

Resolution horizontal: X × r
Resolution vertical: X

WB850F sensor resolution

Sensor width = 6.16 mm
Sensor height = 4.62 mm
Effective megapixels = 16.20

r = 6.16/4.62 = 1.33

X = √	16.20 × 1000000	= 3490
	1.33

Resolution horizontal: X × r = 3490 × 1.33 = 4642
Resolution vertical: X = 3490

Sensor resolution = 4642 x 3490

S110 sensor resolution

Sensor width = 7.53 mm
Sensor height = 5.64 mm
Effective megapixels = 12.10

r = 7.53/5.64 = 1.34

X = √	12.10 × 1000000	= 3005
	1.34

Resolution horizontal: X × r = 3005 × 1.34 = 4027
Resolution vertical: X = 3005

Sensor resolution = 4027 x 3005

Crop factor

Crop factor or focal length multiplier is calculated by dividing the diagonal of 35 mm film (43.27 mm) with the diagonal of the sensor.

Crop factor =	43.27 mm
	sensor diagonal in mm

WB850F crop factor

Sensor diagonal in mm = 7.70 mm

Crop factor =	43.27	= 5.62
	7.70

S110 crop factor

Sensor diagonal in mm = 9.41 mm

Crop factor =	43.27	= 4.6
	9.41

35 mm equivalent aperture

Equivalent aperture (in 135 film terms) is calculated by multiplying lens aperture with crop factor (a.k.a. focal length multiplier).

WB850F equivalent aperture

Crop factor = 5.62
Aperture = f2.8 - f5.9

35-mm equivalent aperture = (f2.8 - f5.9) × 5.62 = f15.7 - f33.2

S110 equivalent aperture

Crop factor = 4.6
Aperture = f2.0 - f5.9

35-mm equivalent aperture = (f2.0 - f5.9) × 4.6 = f9.2 - f27.1

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